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SOLVED: Can someone explain the steps clearly in more detail? I thought the uniform expected value formula was (a b)/2. Thanks.Example 4.6: A number X is picked uniformly at random from 1 to 100. What is the expected value of X^2? The random variable X^2 is equal to f(X), where f(x) = 2. This gives:E[X^2] = ∑(x^2 * P(X=x)) = ∑(x^2/100) = (1/100) * ∑(x^2)Using the fact that the sum of the first n squares is n(n 1)(2n 1)/6, we can simplify the equation further:E[X^2] = (1/100) * (100 * 1

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