2023年10月15日 · Reflectivity is the square of the magnitude of the ratio of the reflected electric field to the incident electric field at a surface boundary. Reflectance is the ratio of the total reflected power to the total incident power. For an infinitely thick material, reflectivity and reflectance are the same.

2018年9月14日 · Why does reflectivity suddenly change around critical angle? For example, consider the situation when incident light travel in dielectrics A and go in to dielectric B. Assume the dielectric constant $\epsilon_A=2.25$ and $\epsilon_B=1.25$. Total internal reflection occur when incident angle is around 46,7 degree.

However the amount of light metals absorb, instead of reflecting, generally increases with increasing temperature because you get more scattering of the conduction electrons by lattice vibrations. So the metal remains mirror-like as it is heated, but the reflection gets gradually darker. However the decrease in reflectivity will generally be small.

2018年8月22日 · I am trying to write a code that calculates Neutron/X-ray reflectivity profile of a multilayered system using Parrat algorithm.

2014年2月11日 · $\begingroup$ Most mirrors are aluminum second-surface mirrors, which have an average reflectivity in the visible range of roughly 90%. So yes, there is loss. $\endgroup$ – DumpsterDoofus

2013年4月3日 · So if the emissivity is high for infra-red that doesn't clash with the reflectivity being high for visible light. This (or rather it's converse) is exactly why greenhouses heat up in visible light. They have a high emissivity and low reflectivity at visible wavelengths but a low emissivity and high reflectivity at IR wavelengths.

2020年3月28日 · How do you calculate the reflectivity of material from its conductivity? For example, gold at v=9x10^12/s (this problem is from the electronic property of material by Hummel). Is it possible to use '

2017年8月29日 · Reflectivity, Absorptivity, and Transmissivity are defined as being fractions of the original incident light. So you could have 30% reflected, 10% absorbed, and then you would know 60% was transmitted since the remaining light had to go somewhere (conservation of energy), for a total of 100% which is equal to 1.

2012年4月24日 · In physics, the reflectivity of a surface is described by Fresnel Equations. One of the parameters of this equations is the refractive index which in general depends on the wavelength of light used. So surfaces that reflect visible light need not be good reflectors in another wavelength.

2021年6月15日 · It seems like for a more metallic material ($\epsilon_r$ << 0), increasing $\epsilon_i$ decreases the reflectivity, which I would understand as an increase in damping of free electron plasmon oscillations upon the surface …