So the equation \(x^2 + bx + c = 0 \) becomes ... right)^2 - c\) which can then be solved by taking the square root of both sides. Start by following the formula: \(x^2 + bx + c = \left(x ...

It is not possible to find the square root of a negative number, so the equation has no solutions. The graph of \(y = x^2 + 2x + 5\) does not cross or touch the x-axis so the equation \(x^2 + 2x ...